Question

A telescope has an objective of diameter 2.5 m. What is its angular resolution when it observes at 5500 Å?​

Answer 1

$\huge\underline\frak{\fbox{AnSwEr :-}}$

Solution: Angular resolution, Δθ = 1.22λ /

a being the diameter of the aperture

= 1.22 x 5.5 x 10-7 / 2.5

= 2.684 x 10-7 rad

= 0.06 arcsec

Answer 2

Answer:

The correct answer will be -

The resolution of the telescope will be 2.684 × 10⁻⁷ Rad.

Step-by-step explanation:

Given in the question -

• There is a telescope that has an objective of diameter 2.5 m.

We have to find its angular resolution when it observes at 5500 Angstroms.

We know that the angular resolution is the smallest angle between two objects that can be seen clearly to be separate.

It is given by,

$Resolution = \frac{1.22\lambda}{d}$

Given,

$\lambda = 5500\times 10^{-10}\ m\\\\d = 2.5\ m$

Put the know values

Resolution = $\frac{1.22\times 5500\times 10^{-10}}{2.5} = 2.684\times 10^{-7} \ rad$

So, The resolution of the telescope will be 2.684 × 10⁻⁷ Rad.

#SPJ3