Question

A television is on sale for 30000.If the sale price is 10% less than the regular price, what was the regular price? Give your answer to the nearest one hundredth. ​

Answer 1

Answer:

T.V on sale for $600 . the sale price is 20 % less than regular price. What was the regular price in dollars? Give answer to nearest one hundredth.

Step-by-step explanation:

Given the current price of a TV = $600

The current price is the price after 20% cut:

Then let us assume that x is the original price of the TV before reduction.

Then :

==> 600 = x - (20% * x)

==> 600 = x - ( 20/100) x

==> 600 = x - ( 0.2) x

==> 600 = 0.8 x

Now divide by 0,8

==> x = 600/ 0.8 = 750

Answer 2

Given :-

Sale price = 30,000

Sale percentage = 10%

To Find :-

The regular price

Solution :-

Let the regular price be x

Now,

Reduced price = 10% of x

$=\: {\dfrac{10 \times x}{100}}$

$=\: {\dfrac{x}{10}}$

Sale price = Regular price - Reduced price

$=\: x\: -\: {\dfrac{x}{10}}$

$=\: {\dfrac{10x - x}{10}}$

$=\: {\dfrac{9x}{10}}$

According to question ,

${\dfrac{9x}{10}}\: =\: 30000$

$=>\: x\: =\: {\dfrac{30000 \times 10}{9}}$

=> x = 33333.33

Therefore, regular price was 33,333.33