Physics, asked by ritika4590, 1 year ago

A television set having a power rating of 120 watt and electric lawnmower of power rating 1kw are both connected to a 240volt supply. If 3A,5A and 10A fuses are available state which is the most appropriate for each appliances ​

Answers

Answered by stuffin
33

Television

power = 120 w

p.d = 240 v

I = p / v

I = 120 / 240 = 0.5

fuse can be used 3A

lawnmower

power = 1000w

p.d = 240 v

I = 1000/ 240 = 4.16

fuse can be used = 5A


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Answered by jotshnamurugesan
0

Explanation:

Given

P = 120w

v = 240 v

I = ?

=

I = p / v

I = 120/240

I = 0.5 A

Hence, Fuse 3A can be used

lawnmower

p=1000w

v=230v

I = ?

P=VI

I = P/ V

I =1000/240

I = 4.16 A .

Hence ,Fuse 5A can be used.

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