A television set having a power rating of 120 watt and electric lawnmower of power rating 1kw are both connected to a 240volt supply. If 3A,5A and 10A fuses are available state which is the most appropriate for each appliances
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Television
power = 120 w
p.d = 240 v
I = p / v
I = 120 / 240 = 0.5
fuse can be used 3A
lawnmower
power = 1000w
p.d = 240 v
I = 1000/ 240 = 4.16
fuse can be used = 5A
stuffin:
whats
Answered by
0
Explanation:
Given
P = 120w
v = 240 v
I = ?
=
I = p / v
I = 120/240
I = 0.5 A
Hence, Fuse 3A can be used
lawnmower
p=1000w
v=230v
I = ?
P=VI
I = P/ V
I =1000/240
I = 4.16 A .
Hence ,Fuse 5A can be used.
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