Question

A tempo carries 325 kg mangoes in one trip so it carries 1950 kg mangoes in ………….. trios.

Answer 1

By dividing 1950 by 325 we get the answer as 6trip

Answer 2

Given:

Weight of mangoes in one trip = 325 kg

To find:

No. of trips required to carry 1950 kg mangoes.

Solution:

In one trip, the tempo can carry 325kg mangoes. Now, we have 1950 kg mangoes, which has to be carried in unknown no. of trips.

Let $x$ be the no. of trips that are required by the tempo to carry 1950 kg mangoes. To determine the value of $x$, divide 1950 by 325.

No. of trips required by tempo to carry 1925 kg mangoes = Weight of mangoes that need to be carried/Weight of mangoes carried in one trip

$x=\frac{1950}{325}$

$x=6$

Hence, the tempo has to carry out 6 trips to transport 1950kg mangoes.

No. of trips required by the tempo to carry 1950kg mangoes is 6.