Question

A TEN METRE LONG ROD IS TO BE BENT TO MAKE A RECTANGLE. ITS LENGTH SHOULD BE ONE METRE MORE THAN THEN THE BREADTH. WHAT SHOULD BE THE LENGTH AND BREADTH?

Answer 1

Step-by-step explanation:

Given :-

A 10 m long rod is to be bent to make a rectangle. Its length should be one meter more than the breadth .

To find :-

What should be the length and breadth ?

Solution :-

Given that

The length of the rod = 10 m

The total length = Perimeter of the rod

It is bent to make a rectangle then

Perimeter of the rectangle = 10 m

We know that

Perimeter of a rectangle = 2(l+b) units

=> 2(l+b) = 10 m

=> l+b = 10/2

=> l+b = 5 m ---------(1)

Given that

Length = breadth +1 m

=> l = (b+1) m

(1) becomes

=> b+1+b = 5

=> 2b+1 = 5

=> 2b = 5-1

=> 2b = 4

=> b = 4/2

=> b = 2 m

Breadth = 2m

and Length = 2+1 = 3 m

Answer:-

The length of the the rectangle = 3 m

The breadth if the rectangle = 2 m

Used formulae:-

→ Perimeter of a rectangle = 2(l+b) units

• l = length
• b = breadth

Answer 2

Step-by-step explanation:

let the length be X+1 and breadth=X perimeter= 2(X+1+X)

2(2X+1)=10

4X+2=10

4X=8

there fore X=2meter

length is 2+1=3

breadth is 2

76

I hope this helps