A tennis ball being dropped from a certain height reached the ground after 4 sec. If no additional force was applied except gravitational force determine the height from which ball was dropped
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Answer:
Uniformly accelerated otion.
So for last 6m distance travelled
As we know
S=ut+21at2
Given :-
S=6m
u=?
t=0.2 sec
a=g=9.8m/s2
s=ut+21at2→6=4(0.2)+4.9×0.01
u=29m/s
For distance x,u=0,v=29m/s
a=g=9.8m/s2
s=2av2−u2⇒2×9.8292−02⇒42.05
Total distance =42.05+6
=48m
Step-by-step explanation:
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