a tennis ball hit the with a tennis racket and the change in the momentum of the ball is 4 kgm/s.if the collision time of the ball and racket is 0.01 sec.what is the magnitude of the force exerted by the ball on the racket
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A/Q :-
Force = momentum/time
=4/0.01
=400kg m/s^2
=400 N
Force = momentum/time
=4/0.01
=400kg m/s^2
=400 N
JunaidMirza:
4/0.01 ≠ 0.04
sorry !! that was written mistakely .. 4/0.01= 400N
tnqq
Atleast chose correct answer as Brainliest.
hmm
Answered by
6
Force = Rate of change of momentum
F = 4 / 0.01
F = 400 N
F = 4 / 0.01
F = 400 N
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