Physics, asked by zayanmaqsood, 11 months ago

A tennis ball is hit upwards at a speed of 15 m/s. • How high does the ball go? How long does it take to hit the ground

Answers

Answered by DrStudy
4

Answer:

Initial velocity of the tennis ball= 15/s

Final velocity = 0 (before falling down at the highest point on the air the final velocity will become zero.)

Acceleration due to gravity = -9.8 m/s^2 (this is negative as the ball goes opposite the force of gravity)

Lets find the time first with which it will hit the ground-

v= u + gt

=> 0 = 15 + (-9.8) × t

=> 0 = 15 - 9.8t

=> -15 = -9.8t

=> -15/-9.8 = t

=> 1.57894737 = t

=> 1.6 = t (for convenience by rounding off I have taken 1.6 s)

Now, we will find the height-

h= ut + 1/2 gt^2

= 15 × 1.6 + 1/2 × (-9.8) × 1.6 × 1.6

= 24 + (-4.9) × 2.56

= 24 + (-12.544)

= 24 - 12.544

= 12.544 m

Thus, time is 1.6 s and height is 12.544 m.

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