Question

A tennis ball is thrown 30° with a velocity of 35 m/s.
A.what is that maximum height reached by ball?
B. what is the horizontal displacement of the ball?​

Answer 1

Answer:

A-maximum height reached by a ball is 0.45 meters. Hence, this is the required solution.

B-y = 0.5 • g • t2

(equation for vertical displacement for a horizontally launched projectile)

where g is -9.8 m/s/s and t is the time in seconds. The above equation pertains to a projectile with no initial vertical velocity and as such predicts the vertical distance that a projectile falls if dropped from rest. It was also discussed earlier, that the force of gravity does not influence the horizontal motion of a projectile. The horizontal displacement of a projectile is only influenced by the speed at which it moves horizontally (vix) and the amount of time (t) that it has been moving horizontally. Thus, if the horizontal displacement (x) of a projectile were represented by an equation, then that equation would be written as