Physics, asked by shruti6656, 1 year ago

a tennis ball is thrown up and reaches a height of 4.05 metre before coming down what was its initial velocity how much total time will it take to come down assume G is equal to 10 metre per second square​

Answers

Answered by Tyooioo
14

Answer:

Displacement (s) = 4.05 m

g = -10 m/s² Final velocity (v) = 0 m/s

To find: Initial velocity (u) = ? ttotal (t) = ?

Formulae: v² = u² + 2gs, u + gt

ttotal = 2 × t

Solution: v² = u² + 2gs

0² = u² + 2 × (-10) × 4.05

0 = u² - 81

u² = 81

u = 9 m/s

v = u + gt

0 = 9 + (-10) × t

10 t = 9

t = 0.9 s

Time of ascent = Time of descent ttotal = 2t

= 2 × 0.9 = 1.8 s

The initial velocity was 9 m/s and total time taken to come down, is 1.8 s.

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Answered by kalkalaunda
1

Answer:

A tennis ball is thrown up and reaches a height of 4.05m before coming down. What was its

initial velocity? How much total time it will take to come down? Assume g = 10m/s squared

Explanation:

above one is correct

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