a tennis ball is thrown up and reaches a height of 4.05 metre before coming down what was its initial velocity how much total time will it take to come down assume G is equal to 10 metre per second square
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Answer:
Displacement (s) = 4.05 m
g = -10 m/s² Final velocity (v) = 0 m/s
To find: Initial velocity (u) = ? ttotal (t) = ?
Formulae: v² = u² + 2gs, u + gt
ttotal = 2 × t
Solution: v² = u² + 2gs
0² = u² + 2 × (-10) × 4.05
0 = u² - 81
u² = 81
u = 9 m/s
v = u + gt
0 = 9 + (-10) × t
10 t = 9
t = 0.9 s
Time of ascent = Time of descent ttotal = 2t
= 2 × 0.9 = 1.8 s
The initial velocity was 9 m/s and total time taken to come down, is 1.8 s.
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Answer:
A tennis ball is thrown up and reaches a height of 4.05m before coming down. What was its
initial velocity? How much total time it will take to come down? Assume g = 10m/s squared
Explanation:
above one is correct
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