A tennis ball is thrown up and reaches a height of 4.05 before coming down.what was its initial velocity?(g=10m/S2
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Explanation:
s = 4.05m
v = 0m/s
g = 10m/s²
by using v²-u²=2gs
0²-u²= 2×10×-4.05
-u² = -81
u = 9
Therefore Initial velocity = 9m/s
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