Question

A tennis ball is thrown up and reaches a height of 4.05m before coming down.what was its initial velocity?how much total time will it take to come down?(assume g=10m/s²)​

Answer 1

Answer:

u=√2gh

u=√2×10×4.05

u=√20×4.05

u=√81

u=9m/sec

h=1/2gt^2

4.05=1/2×10×t^2

(4.05×2)/10=t^2

81÷10=t^2

8.1=t^2

√8.1=t^2

2.84s=t (approximately)

Answer 2

Answer:

u=√2gh

u=√2×10×4.05

u=√20×4.05

u=√81

u=9m/sec

h=1/2gt^2

4.05=1/2×10×t^2

(4.05×2)/10=t^2

81÷10=t^2

8.1=t^2

√8.1=t^2

2.84s=t (approximately)