A tennis ball is thrown upwards from the edge of a cliff with a speed of 10\,\dfrac{\text m}{\text s}10 s m 10, start fraction, start text, m, end text, divided by, start text, s, end text, end fraction. It lands on the ground below the cliff 3.03.03, point, 0 seconds later. We can ignore air resistance.
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Explanation:
Explanation:
Given A tennis ball is thrown upwards from the edge of a cliff with a speed of 10 m/s. It lands on the ground below the cliff 3.0 seconds later. We can ignore air resistance. Find the displacement of the tennis ball.
- We have initial velocity = 10 m/s
- Final velocity = - 10 m/s
- Acceleration due to gravity = 20 m/s^2
- So from equation of motion we have
- v = u + at
- so -10 = 10 + (-10) t
- So – 20 = - 10 t
- Or t = 2 secs
- Now we have
- Initial velocity = - 10 m/s
- Time = total time – time taken for first half
- = 3 – 2
- = 1 sec
- Now using the equation of motion to find displacement we have,
- S = ut + ½ at^2
- S = - 10(1) + ½ x (- 10) (1)^2
- S = - 10 + (- 5)
- S = - 10 – 5
- Or S = - 15 m
- Therefore displacement of tennis ball is – 15 m
Reference link will be
https://brainly.in/question/24227298
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