A tennis racket hits a sand-filled tennis ball with a force of 5.5 N. While the 0.4 kg ball is in contact with the racket, what is its acceleration?
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Answer:
force =F= 5.5 N
mass = 0.4 kg
...
then wkt
F =MA
A=F/M
A= 5.5 / 0.4 = 55 /4 =13.75 metere /sec square
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