Question

A tensile stress of 50 N/m produces a change of
0.1 m in a wire of length 1 m. The young modulus of elasticity is?

A) 50
B) 500
C) 0
D) 5000​

Answer 1

Given:

• Tensile stress = 50 N/m

• Change in confrigation =∆l = 0.1 m

• Orginal confrigation = 1m

To find:

Young modulus of elasticity

• Theory:

Young modulus of elasticity (Y):

It is defined as the ratio of normal stress to the longitudinal strain within the elastic limit.

Y = stress/strain

Stress = F/A

Strain = change in configuration/ original configuration= ∆l/l

• Solution  

We have to find the young modulus

We know  that,

Young modulus = stress/strain

Young modulus = (F/A)/(∆l/l)

Given,

F/A = 50 and l = 1 and ∆l = 1

• Then put  the given values

Young modulus = [ 50/(0.1) ]/1

= 50 × 10

= 500

Hence,

The correct option is B)500

- - -

• More about the topic

• Tensile stress: the length of the rod is increased on application deforming force over and then stress produced in the rod is called tensile stress.

• Strain = the ratio of change in configuration to the original configuration is called this strain .

Answer 2

A tensile stress of 50 N/m produces a change of

0.1 m in a wire of length 1 m. The young modulus of elasticity is?

A) 50

B) 500

C) 0

D) 5000

answer

B)500