A tent consists of a frustum of a cone surmounted by a cone. If the diameter of the upper and the 4 lower circular ends of the frustum be 14m and 26m respectively, the height of the frustum be 8m and the slant height of the surmounted conical portion be 12m, Find the area of canvas required to make the tent.
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Answer:
For the frustum:
Upper diameter = 14 m
Upper Radius, r = 7 m
Lower diameter = 26 m
Lower Radius, R = 13 m
Height of the frustum= h = 8 m
Slant height l =
/7
For the conical part:
Radius of the base = r = 7 m
Slant height = L =12 m
Total surface area of the tent = Curved area of frustum + Curved area of the cone
πl ( R + r ) + πrl
22/7 × 10 (13 + 7) + 22/7 ×7×12
22/7(200 + 84)
892.5 Answer
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