Question

A tent in the form of right circular cylinder which is closed. The diameter of the cylinder is 24m and height of the cylindrical portion is 11m. Find the area of the canvas required for the tent. Also, find the maximum length off the rod which can put in the tent.

Answer 1

1282.28 sq. m

26.4 m

Step-by-step explanation:

The cylindrical tent has a diameter of 24 m and the height is 11 m.

So, the area of the canvas required for the tent will be = 2πrh + πr²

{Where r is the radius of the tent and h is its height}

= $2 \times \frac{22}{7}\times 12 \times 11 + \frac{22}{7}\times 12^{2}$

= 1282.28 sq .m

Now, the maximum length of the rod which can put in the tent = $\sqrt{d^{2} + h^{2}}$

{Where d is the diameter and h is the height of the lent}

= $\sqrt{24^{2} + 11^{2}}$

= 26.4 m