Question

A tent in the shape of cylinder surmounted by a conical top. If the height

and diameter of the cylindrical part are 3.5 m and 6 m respectively, and the

slant height of the top is 2.8 m. Find the area of the canvas used for

making the tent. Also, find the cost of the canvas of the tent at the rate of

500 per m2

​

Answer 1

ANSWER

Area ofCanvas=Curved Area of Cone+Curved Surface Area of the Cylinder

Lets calculate the Curved Surface area of Cone:

Diameter of cone=Diameter of Cylinder=4 m

⟹radius=

2

4

=2 m

Slant height=l=2.8 m

Curved Surface area of Cone=πrl

=

7

22

×2×2.8=17.6 m

2

Curved Surface area of Cylinder=2πrh

=2×

7

22

×2×2.1=26.4 m

2

∴The Area of Canvas=17.6+26.4=44m

2

Now,

Cost of the canvas of the tent for 1 m

2

=Rs 500

Cost of the canvas of the tent for 44 m

2

=500×44=Rs 22000

∴Total Cost=22000 rupees