Question

a tent is cylindrical to a height of 4.8 M and conical about it the radius of the base is 4.5m and total height of the tent is 10.8 m .find the canvas required for the tent in square meters?

Answer 1

Canvas required = CSA of cone + CSA of cylinder
csa of cone is 22/7 × r × l 
csa of cyl. is 2 × 22/7 × r × h     h of cone = 10.8 - 4.8
l=√(4.5)²+(6 )²= 7.5
canvas used= 22/7 × 4.5 ×7.5 + 2 ×22/7 × 4.5 × 4.8
                    =742.5/7 + 950.4/7
                    =106.07 + 135.77
                     = 241.84 cm²
i thinks its right

Answer 2

 The canvas required for the tent is 241.842 sq.m.

Step-by-step explanation:

Height of cylindrical part h = 4.8 m

Total height of the tent is 10.8 m

So, height of conical part H= 10.8  - 4.8 m = 6 m

Radius r = 4.5 m

Tent required = Curved surface area of cone +Curved surface area of cone

Tent required = $2 \pi r h + \pi r \sqrt {H^2+r^2}$

Tent required = $2 \times \frac{22}{7} \times 4.5 \times 4.8+\frac{22}{7} \times 4.5 \times \sqrt{6^2+4.5^2}=241.842 m^2$

Hence  the canvas required for the tent is 241.842 sq.m.

#Learn more:

The height of a conical tent is 12 m and the base radius is 35 M find the Canvas required for the tent

https://brainly.in/question/7875095