Question

A tent is cylindrical to a height of 4.8 m. and conical above it.The radius of the base is 4.5m. and total height of the tent is 10.8 m.Find the canvas required for the tent in square meters.Canvas area=cylinder part area+cone part area=2pi.r.h+pi.r.lhere r=4.5mh=4.8ml=root{(4.5)^2+(6)^2}put this and find answer

Answer 1

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Answer 2

Answer:

The area of the canvas is 241.623 m².

Step-by-step explanation:

Given : A tent is cylindrical to a height of 4.8 m. and conical above it.The radius of the base is 4.5 m and total height of the tent is 10.8 m.

To find : The canvas required for the tent in square meters?

Solution :

We have given that,

Radius of the conical= Radius of the cylinder r= 4.5 m

Height of conical above = Total height of tent - Height of cylinder

Height of conical above = 10.8 - 4.8 = 6 m 

The slant height formula is

$l=\sqrt{r^2+h^2}$

$l=\sqrt{4.5^2+6^2}$

$l=\sqrt{20.25+36}$

$l=\sqrt{56.25}$

$l=7.5$

The area of the canvas is given by,

Canvas required for tent = C.S.A of cone  + C.S.A of cylinder 

$A=\pi r l+2\pi rh$

$A=\pi r (l+2h)$

$A=3.14\times 4.5(7.5+2\times 4.8)$

$A=3.14\times 4.5(7.5+9.6)$

$A=3.14\times 4.5\times 17.1$

$A=241.623$

Therefore, The area of the canvas is 241.623 m².