A tent is in a shape of
shape of a cylinder, surmounted
by
a conical top. If the
height
and diameter of the cylindrical part
2.1m and 4m_respectively
and the slant height of the top is 2.8 m. find the
area of the canvas used for makeup the tent.
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from the question, we know that
the diameter = d = 4 m
l = 2.8 m (slant height)
the radius of the cylinder is equal to the radius of the cylinder
so, r = 4/2 = 2 m
also, we know the height of the cylinder (h) is 2.1 m
so, the required surface area of the given tent = surface area of the cone (the top) + surface area of the cylinder(the base)
= πrl + 2πrh
= πr (l+2h)
now, substituting the values and solving it we get the value as 44 m^2
∴ the cost of the canvas at the rate of rs. 500 per m^2 for the tent will be
= surface area × cost/ m^2
= 44 × 500
so, rs. 22000 will be the total cost of the canvas
hope it's helpful.....:)
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