Question

A tent is in form of a right circular cylinder surmounted by a cone.The diameter of the cylinder is 24 m.The height of the cylindrical portion is 11 m, while the vertex of the cone is 16 m above the ground.Find the area of the canvas required for the tent.

Answer 1

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Answer 2

Answer:

1318.8 sq,m,

Step-by-step explanation:

We are given that A tent is in form of a right circular cylinder surmounted by a cone.

Diameter of cylinder = 24 m

Radius of cylinder = $\frac{24}{2} = 12 m$

Height of cylinder = 11 m

CSA of cylinder = $2 \pi r h$

                           = $2 \times 3.14 \times 12 \times 11$

                           = $828.96 m^2$

Radius of cone = 12 m

The vertex of the cone is 16 m above the ground.

The height of cone =16-  Height of  cylinder = 16- 11 = 5 m

Curved surface area of cone = $\pi r \sqrt{h^2+r^2}$

                                                = $3.14 \times 12 \times  \sqrt{5^2+12^2}$  

                                                = $489.84 m^2$  

Total area of canvas required = $489.84 m^2 +828.96  m^2=1318.8 m^2$  

Hence the area of the canvas required for the tent is 1318.8 sq,m,