A tent is in the form of a cylinder of diameter 15 and height 2.4m surmounted by a cone of equal base and height 4m . find the capacity of tent and the cost of the canvas at 50 rs
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Answer:
Diameter of cylinder=15m
∴Radius of cylinder=
2
15
=7.5m
Height h
1
=2.4m
Height of cone, h
2
=4m
Capacity of cone=πr
2
h
1
+
3
1
πr
2
h
2
=πr
2
(h
1
+
3
h
2
)
=
7
22
×(7.5)
2
(2.4+
3
4
)
=
7
4620
=660m
2
Slant height of cone=
r
2
+h
2
2
=
(7.5)
2
+(4)
2
=8.5m
CSA of cone=πrl=
7
22
×7.5×8.5
=200.35m
2
CSA of cylindrical part=2πrh=2×
7
22
×7.5×2.4
=113.14m
2
Total CSA of tent=200.35+113.14=313.49m
2
Therefore cost of canvas=313.49×50=Rs. 15674.5
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