Question

a tent is in the form of a cylinder of diameter 4.2 metre and height for sir mounted by a cone of equal base and height 2.8 metre find the capacity of the tent and the cost of Canvas for making the tent at rupees hundred square metre​

Answer 1

Answer:

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Step-by-step explanation:

CHF vfy fubf is gvtctxr TFC uig please send me a

Answer 2

Given :-

D of Cone and hemisphare = 4.2 m

so , r of / / and / / i = 4.2 /2 = 2. 1 m

H of cylinder = 4 m

h of cone = 2.8 m

solution:-

volume of tent = volume of cone + Volume of cylinder

= 1/3πr^2h + πr^2H

= 1/3*22/7*2.1*2.1*2.8 + 22/7*2.1

*2.1*4

=22/7*2.1*2.1(1/3*2.8+4)

=13.86(14.8/3)

=38.876 m^3 ans.

l = √r^2+h^2

=√2.1*2.1+2.8*2.8

= √7.84+4.91

=√12.25

=3.5m

CSA of tent = CSA of cone +CSA of cylinder

= πrl+2πrH

= 22/7*2.1(3.5+2*4)

= 6.6*11.5

=75.90 m^2 ans.

Cost for making 1m^2 = 100rs

so,cost for making 75.90 m^2=75.90*100

= 7590rs.

ANSWER IT

Step-by-step explanation:

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