Question

A tent is in the form of a right circular cylinder, surmounted by a cone. The height of the cylindrical portion is 10m, while the vertex of the cone is 15m above the ground. The diameter of the cylinder is 18m. The curved surface area of the cylindrical portion is A 2007m2 B 150mm2 c 180mm SKIP​

Answer 1

Area of canvas required for the tent = Curved surface area of the cylindrical portion + Curved surface area of the cone

=(π)rl+2(π)rh

For cylinder:

Radius (r) of the cylinder =12 m

Height(h) of the cylinder =11m

Curved surface area of cylinder =2πrh=2(π)×12×11=264(π)

For cone:

Height (h) of the cone = Height of the vertex from ground − Height of the cylinder

=16−11=5 m

Radius (r) of the cone =12m

Slant height of the cone =lm

l

2

=r

2

+h

2

l=

r

2

+h

2

l=

5

2

+12

2

=13m

Curved Surface area of cone =πrl=π(12)(13)=(156π)m

2

Hence, area of canvas =(264π+156π)m

2

=(420π)m

2

=420×

7

22

=1320m

2

.

$Area of canvas required for the tent = Curved surface area of the cylindrical portion + Curved surface area of the cone </h3><h3>=(π)rl+2(π)rh</h3><h3>For cylinder:</h3><h3>Radius (r) of the cylinder =12 m</h3><h3>Height(h)  of the cylinder =11m</h3><h3>Curved surface area of cylinder =2πrh=2(π)×12×11=264(π)</h3><h3>For cone:</h3><h3>Height (h) of the cone = Height of the vertex from ground − Height of the cylinder</h3><h3>=16−11=5 m</h3><h3>Radius (r) of the cone =12m</h3><h3>Slant height of the cone =lm</h3><h3>l2=r2+h2</h3><h3>l=r2+h2</h3><h3>l=52+122 =13m</h3><h3>Curved Surface area of cone =πrl=π(12)(13)=(156π)m2</h3><h3>Hence, area of canvas =(264π+156π)m2</h3><h3>=(420π)m2=420×722=1320m2.</h3><h3></h3><h3>$

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♥*♡∞:｡.｡Answer by Shreyas｡.｡:∞♡*♥

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