A tent is in the form of a right circular cylinder, surmounted by a cone. The diameter of the cylinder is 24 m. The height of the cylindrical portion is 11 m , while the vertex of the cone is 16 m above the ground. Find the area of canvas required for the tent.
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Area of canvas required= C.S.A of cone + C.S.A of cylinder
Height of cone = 16m-11m = 5m
Height of cylinder=11m
Diameter of cone = Diameter of cylinder= 24m
Radius of cone/cylinder=12m
Slant height of cone = h2+r2 under root
= 13m
Area required= pi*r*l + 2*pi*r*h
= 22/7 x 12m(13m + 2 x 11m )
= 22/7 x 12 (13 + 22m )
= 22/7 x 12(35m)
= 22x 12 x 5m2
= 22 x 60 m2
=1320 m2
=866.64m2
Height of cone = 16m-11m = 5m
Height of cylinder=11m
Diameter of cone = Diameter of cylinder= 24m
Radius of cone/cylinder=12m
Slant height of cone = h2+r2 under root
= 13m
Area required= pi*r*l + 2*pi*r*h
= 22/7 x 12m(13m + 2 x 11m )
= 22/7 x 12 (13 + 22m )
= 22/7 x 12(35m)
= 22x 12 x 5m2
= 22 x 60 m2
=1320 m2
=866.64m2
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