Question

a tent is in the form of a right circular cylinder, surmounted by a cone. the diameter of the cylinder is 24 m. the height of the cylindrical portion is 11 m, while the vertex of the cone is 16 n above the ground. find the area of the canves requried for the tent

Answer 1

$\huge\underline\bold{Answer:-}$

• For cylinder part, we have

1. r = 12 m
2. h = 11 m

• For conical part, we have

1. Height of the cone = ( 16 - 11 ) m = 5 m

$\therefore$ Slant height = $\sf\sqrt{12^2+5^2}m=13m$

Hence, Area of the canvas required

= Curved surface area of cone + Curved surface area of cylinder

$\tt \: \pi \: rl + 2\pi \: rh = \pi \: r(l + 2h) \\ \\ \tt = \frac{22}{7} \times 12 \times (13 + 22) \: {m}^{2} = 1320 \: {m}^{2}$

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