Question

A tent is in the shape of a cylinder surmounted by a cone The diameter of the cylindrical portion is 24 m and height is 11 m.If the vertex of the cone is 16m above the ground,find the area of the canvas uesd to make the tent.

Answer 1

Answer:

The area of the Canvas required for the tent is 1320 cm² .

Step-by-step explanation:

Given :  

Diameter of a right  circular cylinder = 24 m  

Radius of a right circular cylinder, r = 24/2 = 12 cm

Height of the cylindrical portion , H = 11 m

Height of a tent = 16 m

Height of a cone, h  = 16 - 11 = 5 m

Radius of a cone = Radius of a cylinder = 12 cm

Slant height of a cone, l = √r² + h²

l = √12² + 5² = √144 + 25 = √169  

l =  √169

l = 13 cm  

Slant height of a cone, l = 13 cm  

Surface area of the tent , S = curved surface area of a cylinder + curved surface area of a cone

S = 2πrH + πrl

S = πr(2H + l)

S = 22/7 × 12(2 × 11 + 13)

S =  22/7 × 12(22 + 13)

S = 22/7 × 12 × 35

S = 22 × 12 × 5  

S = 1320 cm²

Hence, the area of the Canvas required for the tent is 1320 cm² .

HOPE THIS ANSWER WILL HELP YOU…

Answer 2

Answer:

Area of canvas required=πrl+2πrH

⇒πr

r

2

+h

2

+2πrH=πr(

r

2

+h

2

+2H)

=

7

22

×12(

12

2

+5

2

+2×11)=1320m

2