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A tent is in the shape of a cylinder surmounted by a conical top. If the height and
diameter of the cylindrical part are 2.1 m and 4 m respectively, and the slant height of the
top is 2.8 m, find the area of the canvas used for making the tent. Also, find the cost of
the canvas of the tent at the rate of Rs 500 per m2
. (Note that the base of the tent will not
be covered with canvas.)
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A tent is in the shape of a cylinder surmounted by a conical top. If the height and diameter of the cylindrical part are 2.1 m and 4 m respectively, and the slant height of the top is 2.8 m, find the area of the canvas used for making the tent. Also, find the cost of the canvas of the tent at the rate of Rs 500 per m
2
. (Note that the base of the tent will not be covered with canvas.) (Use π=
7
22
).
October 15, 2019avatar
Roshilla Danduri
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VIDEO EXPLANATION
ANSWER
Given:
Height (h) of the cylindrical part = 2.1 m
Diameter of the cylindrical part = 4 m
Radius of the cylindrical part = 2 m
Slant height (l) of conical part = 2.8 m
Area of canvas used = CSA of conical part + CSA of cylindrical part
=πrl+2πrh
=π×2×2.8+2π×2×2.1
=2π[2.8+4.2]
=2×
7
22
×7
=44m
2
Cost of 1 m
2
canvas =500 rupees
Cost of 44 m
2
canvas =44×500=22000 rupees.
Therefore, it will cost 22000 rupees for making such a tent.
Hyy Dude
[FIGURE IS IN THE ATTACHMENT]
SOLUTION;
Given:
Height (h) of the cylindrical part = 2.1 m
Diameter of the cylindrical part = 3 m
Radius of the cylindrical part = 3/2 m
Slant height (l) of conical part = 2.8 m
Total canvas used = CSA of conical part + CSA of cylindrical part
= πrl + 2πrh
= πr(2h+l)
= (22/7)×3/2(2×2.1+2.8)
= (22/7)×3/2(4.2+2.8)
= (22/7)×3/2(7)
= 11×3
= 33 m²
Cost of 1 m² canvas = ₹ 500
Cost of 44 m² canvas = 33 × 500 = 16500
The cost of Canvas needed to make the tent= ₹ 16500
Hence, it will cost ₹ 16500 for making such a tent.
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