Question

A tent is in the shape of a cylinder surmounted by a conical top. If the height and diameter of the cylindrical part are 2m and 6m respectively and the slant height of the top is 2.4m. Find the area of the canvas used for making the tent. Also, find the cost of the canvas of the tent at the rate of Rs.300 per m²???

Answer 1

Given that,

Height (h) of the cylindrical part = 2.1 m

Diameter of the cylindrical part = 4 m

Radius of the cylindrical part = 2 m

Slant height (l) of conical part = 2.8 m

Area of canvas used = CSA of conical part + CSA of cylindrical part



Cost of 1 m2 canvas = Rs 500

Cost of 44 m2 canvas = 44 × 500 = 22000

Therefore, it will cost Rs 22000 for making such a tent.

Answer 2

Solution:

Given:

➜ A tent is in the shape of a cylinder surmounted by a conical top.

➜ If the height and diameter of the cylindrical part are 2m and 6m respectively and the slant height of the top is 2.4m.

Find:

➜ Find the area of the canvas used for making the tent.

➜ Find the cost of the canvas of the tent at the rate of Rs.300 per m² ?

Given:

• 4m = diameter.
• 2.8 m = slant height of the cone.
• 2.1 m = αheight of the cylinder.

Formula:

➜Surface area of tent = Surface Area of Cone + Surface Area of Cylinder

➜ πrl + 2πrh

➜ πr (l + 2h)

➜ 22/7 × 2 (2.8 + 2 × 2.1)

➜ 44/7 (2.8 + 4.2)

➜ 44/7 × 7 = 44 m²

Formula:

Surface area × cost per meter²

➜ 44 × 500

➜ 22000

Therefore, 22000 will be the total cost of the canvas.

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