Math, asked by gayakesanskruti, 9 months ago

A tent is in the shape of a cylinder surmounted by a conical top.If the height and diameter of the cylindrical part are 2.1 m and 4 m respectively, and the slant height of the top is 2.8 m.find the area of the canvas of the tent at the rate of Rs.500 per square m.

Answers

Answered by Anonymous

Answer:

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Answered by silentlover45

Figure:-

Given:-

Slant height of cone = 2.8m
Height and Diameter of the cylindrical part are 2.1m and 7m.
Cost of the canvas of the tent of 1m² = Rs. 500 per m²

To find:-

find the area of the canvas of the tent at the rate of Rs.500 per square m.

Solutions:-

Height of the cylinder part = 2.1m
Diameter of the cylinder part = 4m
Radius of the cylinder part = 2m
Slant height of conical part = 2.8m

Area of congas used = CSA of conical part + CSA of cylindrical part

=> πrl + 2πrh

=> π × 2 × 2.8 + 2π × 2 × 2.1

=> 2π(2.8 + 2 × 2.1)

=> 2π(2.8 + 4.2)

=> 2π × 7

=> 2 × 22/7 × 7

=> 2 × 22

=> 44m²

Cost of 1m² canvas = Rs 500

Cost of 44m² canvas = 44 × 500

= 22000

Hence, the cost Rs 22000 for making sure a tent.

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A tent is in the shape of a cylinder surmounted by a conical top.If the height and diameter of the cylindrical part are 2.1 m and 4 m respectively, and the slant height of the top is 2.8 m.find the area of the canvas of the tent at the rate of Rs.500 per square m.​