Question

A tent is in the shape of a cylinder surmounted by a conical top. If the height and diameter of the cylindrical part are 2.1 m and 4 m respectively, and the slant height of the top is 2.8 m, find the area of the canvas used for making the tent. Also, find the cost of the canvas of the tent at the rate of Rs 500 per m².

(Note that the base of the tent will not be covered with canvas.)

$[use \: \pi = \frac{22}{7} ]$
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Answer 1

$\huge\underline{\overline{\mid{\bold{ \orange{Given}}\mid}}}$

• Height (h) of the cylindrical part = 2.1 m

• Diameter of the cylindrical part = 4 m

• Radius of the cylindrical part = 2 m

$\huge\underline{\overline{\mid{\bold{ \blue{To \: Find}}\mid}}}$

• Area of the canvas used for making the tent

• the cost of the canvas of the tent at the rate of Rs 500 per m²

$\huge\underline{\overline{\mid{\bold{ \green{Solution}}\mid}}}$

Area of canvas used = CSA of conical part + CSA of cylindrical part

$\tt \implies \pi rl + 2\pi rh$

$\tt\implies \pi \times 2 \times 2.8 + 2\pi \times 2 \times 2.1$

$\tt\implies 2\pi \bigg[2.8 + 2 \times 2.1 \bigg] = 2\pi \bigg[2.8 + 4.2 \bigg] = 2 \times \frac{22}{7} \times 7</p><p></p><p>$

$\tt\implies 44 {m}^{2}$

Cost of 1 m² canvas = RS 500

Cost of 44 m² canvas = 44 × 500 = 22000

Therefore, it will cost Rs 22000 for making such a tent.

Answer 2

Answer:

Given:-

Height = 2.1m

Diameter = 4m; Radius = 4/2 =2m.

Slant height = 2.8m.

Total cost is Rs 22,000 ans.

Learn from the attachment..

Step-by-step explanation:

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