Question

A tent is in the shape of a cylinder surmounted by a conical top of same diameter.If the height and diameter of cylindrical part are 2.1m and 3m respectively and the slant height of conical part is 2.8m,find the cost of canvas needed to make the tent if the canvas is available at the rate of ₹500/sq.mt

Answer 1

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Answer 2

For the conical part:

r = $\sf{\frac{4m}{2}=2m}$

$\sf{slant\:height=2.8m}$

For the cylindrical part:

r = 2m

h = 2.1m

CSA or the whole tent = CSA of cylindrical part + CSA of a conical part.

$\longrightarrow$$\sf{2\pi \: rh + \pi \: rl = \pi \: r(2h + l)}$

$\longrightarrow$$\sf{ \frac{22}{7} \times 2(2 \times 2.1 + 2.8) {m}^{2}}$

$\longrightarrow$$\sf{\frac{22}{7} \times 2(4.2 + 2.8) {m}^{2}}$

$\longrightarrow$$\sf{\frac{22}{7} \times 2 \times 7 {m}^{2}}$

$\longrightarrow$${\boxed{\sf{\red{{44m}^{2}}}}}$

Cost of canvas required for making the tent

$\longrightarrow$ Rs. 44 × 500

$\longrightarrow$ Rs. 22000