Question

A tent is in the shape of a cylinder surmounted by a conical top. If the height and diameter of the cylindrical part are 2.1m and 4m respectively,

Answer 1

2.1 × 4, ask the full question .

Answer 2

For the conical part:

r = $\sf{\frac{4m}{2}=2m}$

$\sf{slant\:height=2.8m}$

For the cylindrical part:

r = 2m

h = 2.1m

CSA or the whole tent = CSA of cylindrical part + CSA of a conical part.

$\longrightarrow$$\sf{2\pi \: rh + \pi \: rl = \pi \: r(2h + l)}$

$\longrightarrow$$\sf{ \frac{22}{7} \times 2(2 \times 2.1 + 2.8) {m}^{2}}$

$\longrightarrow$$\sf{\frac{22}{7} \times 2(4.2 + 2.8) {m}^{2}}$

$\longrightarrow$$\sf{\frac{22}{7} \times 2 \times 7 {m}^{2}}$

$\longrightarrow$${\boxed{\sf{\red{{44m}^{2}}}}}$

Cost of canvas required for making the tent

$\longrightarrow$ Rs. 44 × 500

$\longrightarrow$ Rs. 22000