A tent is in the shape of a right circular cylinder surmounted by a right circular cone, the height of the cylinder and the conical part are 40 m and 21 m respectively. if the base diameter of the tent is 56 m(r=28m)find the area of required canvas to make this that, if 20% of the area of canvas is consumed ki folding and sewing. ANS:-12650m².
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Answer:
Diameter =28 m
Radius =
2
28
=14 m (=r)
Height h=3 m
Curved Surface area of Cylinder =2πrh square unit
=2×
7
22
×14×3
=264m
2
Cone:
radius =14 m; h=10.5 m
Slant height l=
h
2
+r
2
=
(10.5)
2
+14
2
=
306.25
=17.5 m
Curved surface area of cone =πrl square unit
=
7
22
×14×17.5
=770m
2
Total surface area of the tent =264+770=1034m
2
.
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