A tent is in the shape of a right circular cylinder upto a height of 3 m and a cone above
it. The maximum height of the tent above the ground is 13.5 m. Calculate the cost of
painting the inner side of the tent at the rate of 3 per sq. m., if the radius of the base
is 14 m.
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Answer:
CSA of Tent = CSA of cylinder + CSA of cone
= 2rh + rl
= 2 (14) (3) + (14)
= 264 + 14
=264 + 14 (17.5)
= 264 + 770
= 1034 m2.
Cost of painting the inside of tent, i.e., 1034 m2 at the rate of Rs. 2 per sq m = Rs 1034 x 2 = Rs. 2068.
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