Math, asked by rockstargarima0850, 9 months ago

A tent is in the shape of cylinder surmounted by conical top. if the height and the diameter of cylindrical part is 2.1 and 4 m. Find the area of the canavas used for making the tank also find the cost of canavas at the rate of 500m2.

Answers

Answered by Anonymous
1

Answer:

SOLUTION;

Given:

Height (h) of the cylindrical part = 2.1 m

Diameter of the cylindrical part = 3 m

Radius of the cylindrical part = 3/2 m

Slant height (l) of conical part = 2.8 m

Total canvas used = CSA of conical part + CSA of cylindrical part

= πrl + 2πrh

= πr(2h+l)

= (22/7)×3/2(2×2.1+2.8)

= (22/7)×3/2(4.2+2.8)

= (22/7)×3/2(7)

= 11×3

= 33 m²

Cost of 1 m² canvas = ₹ 500

Cost of 44 m² canvas = 33 × 500 = 16500

The cost of Canvas needed to make the tent= ₹ 16500

Hence,  it will cost ₹ 16500 for making such a tent.

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peace!

Answered by ishanpreetsinghsaini
1

Answer:

Area of cylinder + area of cone

and you will get the answer!

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