Question

A tent is in the shape of right circular cylinder upto a height of 3 metres and then become a right circular cone with a maximum height of 13.5m above the ground.Calculate the cost of painting the inner side of the tent at the rate of Rs.2 per square metre,if radius of base is 14m.​

Answer 1

Answer:

here what's ur ques :

A tent is in the shape of right circular cylinder upto a height of 3 metres and then become a right circular cone with a maximum height of 13.5m above the ground.Calculate the cost of painting the inner side of the tent at the rate of Rs.2 per square metre,if radius of base is 14m.

Explain:

CSA of cylinder = 2πrh = (2×227×14×3)m2(2×227×14×3)m2 = 264m2 CSA of cone = πrl

where l = slant height l=r2+h2−−−−−−√=142+(10.5)2−−−−−−−−−−√l=r2+h2=142+(10.5)2

m =196+110.25−−−−−−−−−−

√m=306.25−−−−−

√=196+110.25m=306.25 m = 1705 m

∴ CSA of cone = (227×14×17.5)(227×14×17.5) m = 770m2

∴ Cost of painting = Rs. 2 × Total CSA = Rs.2 × (264 + 770) = Rs. [2 × 1034] = ₹2068

Hope it helps have a great day

Answer 2

Step-by-step explanation:

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