A tent is in the shape of right circular up to height of 3m , and cone above it. The maximum height of tent above ground is 13.5m. Calculate the cost of painting the inner side of tent at rate of RS. 3sq m if radius of base is 14.
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A tent is of the shape of a right circular cylinder upto height of 3 metres and then becomes a right circular cone with maximum height of 13.5 metres above the ground. Calculate the cost of painting the inner side of the tent at the rate of Rs.2 per square metre, if the radius of the base is 14 metres.
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ANSWER
Radius of base of cylindrical portion=14m
Height of cylindrical portion=3m
Curved surface area of cylindrical part=2×
7
22
×14×3
Height of conical part=13.5−3=10.5m
For conical part:r=14m,h=10.5m
l=
(14)
2
+(10.5)
2
=
306.25
l=17.5m
CSA of conical part=πrl=
7
22
×14×17.5=770㎡
∴Total area to be painted=(264+770)㎡=1034㎡
Cost of painting=Rs. (1034×2)=Rs. 2068
Answered By
Disha
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Step-by-step explanation:
A tent is of the shape of a right circular cylinder upto height of 3 metres and then becomes a right circular cone with maximum height of 13.5 metres above the ground. Calculate the cost of painting the inner side of the tent at the rate of Rs.2 per square metre, if the radius of the base is 14 metres.
242864
Share
Study later
ANSWER
Radius of base of cylindrical portion=14m
Height of cylindrical portion=3m
Curved surface area of cylindrical part=2×
7
22
×14×3
Height of conical part=13.5−3=10.5m
For conical part:r=14m,h=10.5m
l=
(14)
2
+(10.5)
2
=
306.25
l=17.5m
CSA of conical part=πrl=
7
22
×14×17.5=770㎡
∴Total area to be painted=(264+770)㎡=1034㎡
Cost of painting=Rs. (1034×2)=Rs. 2068
Answered By
Disha
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