A tent is such that its lower part is cylindrical and upper part is conical. If the height of cylindrical part is 2.1m and radius of cylindrical part is 2m; and slant height of the top is 2.8m. Find the area of the canvas used making the tent. Also find the cost of the canvas of the tent at rate of ₹500 per m^2
Answers
Answer:
tha cost of canvas of the tent is 19785 Rs
The area of the canvas used in making the tent is 44 m²
The cost of the canvas of the tent at the rate of ₹500 per m² is Rs. 22000.
Step-by-step explanation:
It is given that,
The radius of the cylindrical part of the tent, r = 2 m
The height of the cylindrical portion of the tent, h = 2.1 m
The slant height of the conical part of the tent, l = 2.8 m
We know that the radius of the conical part i.e., the upper part of the tent will be the same as the radius of the cylindrical part i.e., the lower part.
Now,
The area of the canvas required in making the tent is given by,
= [C.S.A of Cylinder] + [C.S.A of Cone]
= [2πrh] + [πrl]
= [2 * 22/7 * 2 * 2.1] + [22/7 * 2 * 2.8]
= [26.4] + [17.6]
= 44 m²
The rate of the canvas used = Rs. 500 per m²
Thus,
The total cost of the canvas used in making the tent is,
= Rs. 500 × 44 m²
= Rs. 22000
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