Question

A tent is such that its lower part is cylindrical and upper part is conical. The
height and diameter of cylindrical part is 2.1 m and 3 m. respectively. Slant
height of conical part is 2.8 m. Find the total canvas used in making the test. If
cost of canvas is Rs. 500 per m. Find cost of making the tent.​

Answer 1

Answer:

Useless boys

Step-by-step explanation:

Mere Ghar a deta hu Step-by-step explanation

Answer 2

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From the question, we know that

The diameter = D = 4 m

l = 2.8 m (slant height)

The radius of the cylinder is equal to the radius of the cylinder

So, r = 4/2 = 2 m

Also, we know the height of the cylinder (h) is 2.1 m

So, the required surface area of the given tent = surface area of the cone (the top) + surface area of the cylinder(the base)

= πrl + 2πrh

= πr (l+2h)

Now, substituting the values and solving it we get the value as 44 m^2

∴ The cost of the canvas at the rate of Rs. 500 per m^2 for the tent will be

= Surface area × cost/ m^2

= 44 × 500

So, Rs. 22000 will be the total cost of the canvas

Hope it's Helpful.....:)