Math, asked by Vidyapawarkevale, 1 year ago

A tent of a circus is such that it's lower part is cylindrical & upper part is conical The diameter of the base of the tent is 56m & the height of the cylindrical part is 15m. Total height of the tent is 60 find the area of canvas required to make the tent.

Answers

Answered by ShuchiRecites
10
Answer : 7304 m²

Step-by-step explanation :

Total height of tent = 60 m

Height of cylinderical part = 15 m

Height of conical part = 60 m - 15 m

= 45 m

Diameter of base = 2 × radius

56 m = 2 × radius

28 m = radius

Curved surface area of cylinder

= 2πrh

= 2 × 22/7 × 28 m × 15 m

= 2 × 22 × 4 m × 15 m

= 2640 m²

Curved surface area of cone = πrl

But we don't have l,

l = √( r² + h² )

l = √( 28² + 45² )

l = √2809 m = 53 m

Curved surface area

= 22/7 × 28 m × 53 m

= 22 × 4 m × 53 m

= 4664 m²

Total surface area = ( 2640 + 4664 ) m²

= 7304 m²
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