A tent of a circus is such that it's lower part is cylindrical & upper part is conical The diameter of the base of the tent is 56m & the height of the cylindrical part is 15m. Total height of the tent is 60 find the area of canvas required to make the tent.
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Answer : 7304 m²
Step-by-step explanation :
Total height of tent = 60 m
Height of cylinderical part = 15 m
Height of conical part = 60 m - 15 m
= 45 m
Diameter of base = 2 × radius
56 m = 2 × radius
28 m = radius
Curved surface area of cylinder
= 2πrh
= 2 × 22/7 × 28 m × 15 m
= 2 × 22 × 4 m × 15 m
= 2640 m²
Curved surface area of cone = πrl
But we don't have l,
l = √( r² + h² )
l = √( 28² + 45² )
l = √2809 m = 53 m
Curved surface area
= 22/7 × 28 m × 53 m
= 22 × 4 m × 53 m
= 4664 m²
Total surface area = ( 2640 + 4664 ) m²
= 7304 m²
Step-by-step explanation :
Total height of tent = 60 m
Height of cylinderical part = 15 m
Height of conical part = 60 m - 15 m
= 45 m
Diameter of base = 2 × radius
56 m = 2 × radius
28 m = radius
Curved surface area of cylinder
= 2πrh
= 2 × 22/7 × 28 m × 15 m
= 2 × 22 × 4 m × 15 m
= 2640 m²
Curved surface area of cone = πrl
But we don't have l,
l = √( r² + h² )
l = √( 28² + 45² )
l = √2809 m = 53 m
Curved surface area
= 22/7 × 28 m × 53 m
= 22 × 4 m × 53 m
= 4664 m²
Total surface area = ( 2640 + 4664 ) m²
= 7304 m²
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