Question

A tent of a circus is such that it's lower part is cylindrical & upper part is conical The diameter of the base of the tent is 56m & the height of the cylindrical part is 15m. Total height of the tent is 60 find the area of canvas required to make the tent.

Answer 1

Answer : 7304 m²

Step-by-step explanation :

Total height of tent = 60 m

Height of cylinderical part = 15 m

Height of conical part = 60 m - 15 m

= 45 m

Diameter of base = 2 × radius

56 m = 2 × radius

28 m = radius

Curved surface area of cylinder

= 2πrh

= 2 × 22/7 × 28 m × 15 m

= 2 × 22 × 4 m × 15 m

= 2640 m²

Curved surface area of cone = πrl

But we don't have l,

l = √( r² + h² )

l = √( 28² + 45² )

l = √2809 m = 53 m

Curved surface area

= 22/7 × 28 m × 53 m

= 22 × 4 m × 53 m

= 4664 m²

Total surface area = ( 2640 + 4664 ) m²

= 7304 m²