Question

A tent of height 33 cm is in the form of a right circular
cylinder of diameter 42 cm and height 5 cm surmounted by
a right circular cone of the same diameter. Find the total
surface area of the tent.

I tried this question but there is some mistakes... I guess.
The answer is 2970 cm Sq.

plz check my answer and correct it. ​

Answer 1

Answer:

1320m²

Step-by-step explanation:

Area of canvas required for the tent = Curved surface area of the cylindrical portion + Curved surface area of the cone 

=(π)rl+2(π)rh

For cylinder:

Radius (r) of the cylinder =12 m

Height(h)  of the cylinder =11m

Curved surface area of cylinder =2πrh=2(π)×12×11=264(π)

For cone:

Height (h) of the cone = Height of the vertex from ground − Height of the cylinder

=16−11=5 m

Radius (r) of the cone =12m

Slant height of the cone =lm

l2=r2+h2

l=r2+h2

l=52+122 =13m

Curved Surface area of cone =πrl=π(12)(13)=(156π)m2

Hence, area of canvas =(264π+156π)m2

=(420π)m2=420×722=1320m2.