Question

A tent of height 77 dm is in the form a right circular cylinder of diameter 36 m and height 44 dm surmounted by a right circular cone. Find the cost of the canvas at Rs. 3.50 per m2.

Answer 1

Answer:

Height of tent =77dm

=7.7m

Radius of the cylinder  =18 m

Height of cylinder =44dm =4.4m

Height of cone = (7.7-4.4) m

=3.3m

Curved Surface area of cylinder portion of the tent  

= 2 × (22/7) × 18 × 4.4

= 497.83 m2

Curved surface area of conical tent =π r l

Slant height of cone  

= 18.3m

Curved surface area of cone = (22/7) × 18 × 18.3

= 1035.26m2

Total surface area of the tent = 497.83m2 + 1035.26m2

= 1533.09m2

Total cost of canvas = 3.50 × 1533.09

= Rs 5365.82

Answer 2

ANSWER:-

Given:

A tent of height 77 dm is in the form a right circular cylinder of diameter 36m & height 44dm surmounted by a right circular cone.

To find:

The cost of the canvas at Rs.350m².

Solution:

⚫Height of tent= 77dm

In metre= 7.7m

⚫Diameter of the cylinder=36m

In radius = 36/2

=) 18m

⚫Height of cylinder= 44dm

In metre= 4.4m

⚫Height of cone= (7.7 -4.4)m

=) 3.3m

Curved surface area of cylinder portion of the tent;

=) 2πrh

$= > 2 \times ( \frac{22}{7} ) \times 18 \times 4.4 \\ \\ = > \frac{44}{7} \times 79.2 \\ \\ = > \frac{3484.8}{7} \\ \\ = >497.82 {m}^{2}$

Curved surface area of conical tent=πrl

Slant Height of cone:

$= > \sqrt{(3.3) {}^{2} + 18 {}^{2} } \\ \\ = > \sqrt{10.89 + 324} \\ \\ = > \sqrt{334.89} \\ \\ = > 18.3m$

Curved surface area of cone:

$= > \frac{22}{7} \times 18 \times 18.3 \\ \\ = > \frac{7246.8}{7} \\ \\ = > 1035.26{m}^{2}$

Total Surface area of the tent:

=) 497.83m² + 1035.26m²

=) 1533.09m²

Total cost of canvas:

=) Rs.3.50 × 1533.09

=) Rs.5365.82

The cost of canvas is Rs.5365.82.

Hope it helps ☺️