A tent of height 77 dm is in the form a right circular cylinder of diameter 36 m and height 44 dm surmounted by a right circular cone. Find the cost of the canvas at Rs. 3.50 per m².(Use π=22/7)
Answers
Step-by-step explanation:
hope it helps you good night
The cost of canvas is ₹ 5365.80.
Step-by-step explanation:
Given
Diameter of the cylinder = 36 m
Radius of the cylinder , r = 36 / 2 m = 18 m
The height of the tent = 77 dm
Height of the cylindrical part ,H = 44 dm
Height of the right circular cone , h = (77 – 44) dm = 33 dm = 33/10 = 3.3 m
[1 dm = 1/10 m]
Let the slant height of the cone be (l).
l² = r² + h
l² = (18)² + (3.3)²
l² = 324 + 10.89
l² = 334.89
l = √334.89
l = 18.3 m
slant height of the cone is 18.3 m.
Curved surface area of the cylinder = 2πrh
= 2π × 18 × 4.4 m² ……………….. (1)
Curved surface area of the cone = πrl
= π × 18 × 18.3 m²…………………….. (2)
Total curved surface area of the tent = Curved surface area of the cylinder + Curved surface area of the cone
= 2π × 18 × 4.4 m² + π × 18 × 18.3 m²
[From eq. 1 & 2]
= 18π(2 × 4.4 + 18.3)
= 18π (8.8 + 18.3)
= 18π(27.1)
= 18 × π (27.1)
Cost of canvas = 18 × π (27.1) × ₹ 3.5
= 18 × 22/7 × 27.1 × 3.5
= ₹ 5365.80