Question

a terrestrial telescope has an objective of focal length 180 cm and an eyepiece of a focal length of 5cm the erecting lens has a focal length of 3.5 cm what is the separation between the objective and the eyepiece what is the magnifying power of the telescope can we use the telescope for being the astronomical object

Answer 1

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Answer 2

Hence the magnification of the telescope is 36

Explanation:

We are given that:

• Objective of focal length fo = 180 cm
• Eyepiece of a focal length  fe = 5 cm
• Focal length f = 3.5 cm

Solution:

Formula for magnification is

M = f0 / fe 180 / 5 = 36

Hence the magnification of the telescope is 36