Question

A Tesla Roadster car accelerates from rest at a rate of 7.1m/s2 for a time of 3.9s. Calculate the distance it travels inn this time.

Answer 1

Given:

Initial speed of car,u= 0 m/s

Acceleration of car,a= 7.1 m/s²

Time taken by car,t= 3.9 s

To Find:

Distance travelled by car in given time

Solution:

We know that,

• According to second equation of motion for constant acceleration,

$\pink{\underline{\boxed{\bf{s=ut+\frac{1}{2}at^{2}}}}}$

where,

u is initial velocity

a is acceleration

s is displacement

t is time taken

━━━━━━━━━━━━━━━━━━━━━━━━━

Let the distance covered by Tesla Roadster car in given time be s

So, on applying second equation of motion on car, we get

$\longrightarrow\rm{s=ut+\dfrac{1}{2}at^{2} }$

$\longrightarrow\rm{s=0(3.9)+\dfrac{1}{2}(7.1)(3.9)^{2} }$

$\longrightarrow\rm{s=\dfrac{1}{2}(7.1)(15.21)}$

$\longrightarrow\rm{s=\dfrac{107.991}{2}}$

$\longrightarrow\rm\green{s=53.9955\ m}$

Hence, the distance covered by Tesla Roadster car in 3.9 s is 53.9955 m.

Answer 2

Here, u=0m/s

a=7.1 m/s

t=3.9 s

By using the 3rd equation of motion,

S=ut +1/2 at^2

=0×3.9+1/2×7.1×3.9^2

=0+1/2×7.1×15.21

=1/2×107.991

=53.9955 m