Math, asked by samudralasree, 1 month ago

A test tube contains 25 bacteria, 5 of which are can stay alive for atleast 30 days, 10 of which will die in their second day. 10 of which are already dead.
Given that a randomly chosen bacteria for experiment is alive. What is the probability it will still be alive after one week?
(a)1 ⁄ 3(b)2 ⁄3
(c) 1⁄5 (d)4 ⁄5
Need proper explanation for this

Answers

Answered by haveaniceweekand
0

Answer:

kuta bagarat haramzada dallah

Answered by abhitiwari20182
0

Answer:

A. 1/3

Step-by-step explanation:

It is given that the bacteria is alive

Let A be the event chosen one will live for 30 days.

Let B be the event that chosen one is already dead.

P(\frac{A}{B'}) = \frac{P(A \cap B')}{P(B')} = \frac{5/25}{15/25} = \frac{1}{3}

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