Question

a test tube contains 30ml of boron and water in ratio 7:3.how much water should take to be added to this mixtures that the proportion of water in the mixture becomes 40%​

Answer 1

Explanation:

In the original mixture Milk = 21 liters and water is 9 liters In the new mixture the

ratio of milk and water is 3 : 7 Since milk contents remain the same in both the mixtures

so 21 : x = 3 : 7 i.e. x = 49

Hence water to be added in mixtures = 49-9 = 40 litres

Answer 2

Answer:

The correct answer is 5ml. Therefore, 5 ml of water should be added to this mixtures that the proportion of water in the mixture d becomes 40%.

Explanation:

In a 30ml combination, the chlorine to water ratio is 7:3.

Consequently, the mixture comprises 9 ml of water and 21 ml of chlorine.

Here, the combination contains 30% water, but if more water is added, the chlorine content will remain the same while the water content rises to 40%.

As a result, 60 percent of the entire volume of the resulting combination will be made up of chlorine.

Therefore, volume of chlorine = total volume x 60/100

And we know that according to the question. The volume of chlorine is given as 21ml, substituting that value in the above equation we get :

21 = total volume x 60/100

That gives us, total volume = 21/0.6 = 35ml

It is obvious that the final mixed volume, which is 35 ml and 5 ml higher than the initial amount, is correct.

As a result, the mixture receives 5 ml of water.

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