a test tube has a lower part hemispherical and upper part cylindrical with same radius. If 5159/6 cm cube of water is added the test tube will be just completely filled. but if 20002 cm cube of eater is added 5 cm of height will remain empty.find the radius and height of the cylindrical part
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Given
a test tube has a lower part hemispherical and upper part cylindrical with same radius. If 5159/6 cm cube of water is added the test tube will be just completely filled. but if 2002 / 3 cm cube of eater is added 5 cm of height will remain empty.find the radius and height of the cylindrical part
- Volume of total tube will be
- 2/3 π r^3 + π r^2h = 5159 / 6 cm^3 -----------1
- Also
- 2/3 π r^3 + π r^2 (h – 5) = 2002 / 3 cm^3---------2
- Subtracting both the equations we get
- 5 πr^2 = 5159 / 6 – 2002 / 3
- 5πr^2 = 5159 – 4004 / 6
- = 1155 / 6
- 30 πr^2 = 1155
- Or r^2 = 49 / 4
- Or r = 7 / 2
- Substituting in tπe above equation we get
- π(7/2)^2 (2/3 x 7/2 + h) = 5159 / 6
- π(49/4)(7 + 3h / 3) = 5159 / 6
- 77/2 (7 + 3h) = 5159 / 2
- 7 + 3h = 5159 / 77
- 7 + 3h = 67
- 3h = 60
- Or h = 20
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